Match the List-I with List-II.

Choose the correct answer from the options given below.

Question

Match the List-I with List-II.

Choose the correct answer from the options given below.

CGP EDU Academic Team · Accepted Answer

The correct answer is A. Step 1: Analyze the changes in bond order and magnetic properties for each transformation.1. **A. N2 → N2+**  Bond order of N2 is 3 (as both the bonds are sigma and two pi bonds).For N2+, removing one electron from the antibonding orbital decreases the bond order to 2.5.Since positively charged species typically have fewer unpaired electrons, the magnetic property may change. Therefore, this matches with (iv): Bond order decreases and magnetic property changes.2. **B. O2 → O22+**  Bond order of O2 = 2.For O22+, two electrons are removed from the antibonding pi orbitals, yielding a bond order of 2 as well.As both species are diatomic, their magnetic properties do not change. Hence, this corresponds with (ii): Bond order decreases and magnetic property not changes.3. **C. B2 → B2+**  Bond order of B2 is 1.For B2+, one electron is removed from a bonding orbital, leaving the bond order at 0.5.This results in an increase in bond order (going from 1 to 0.5), but its magnetic property doesn’t change since it remains paramagnetic.Thus, this matches with (iii): Bond order increases and magnetic property not changes.4. **D. NO- → NO**  Bond order of NO- is 2.5.In NO, one electron is removed thus increasing it to a bond order of 3.Similarly, the magnetic property doesn’t change, so this corresponds with (i): Bond order increases and magnetic property changes.Conclusion: The correct pairs are A-(iv), B-(ii), C-(i), D-(iii). Therefore, the answer is option A.

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